Optimization Papers

The Cost of an Unknown Horizon for the Last Iterate of Clipped SGD under Heavy-Tailed Noise

Peng et al.

Without a known horizon, the best time-uniform rate for the last iterate of clipped SGD under heavy-tailed noise is \(\tilde O(t^{-\beta_p})\) with \(\beta_p = 2(p-1)/(3p-1)\), strictly worse than the known-horizon rate.

Filed under Optimization, Learning theory

Training is usually stopped at a time that depends on the data, so a useful guarantee for the last iterate must hold at every time at once. The authors study clipped stochastic gradient descent on smooth convex objectives when the gradient noise has a bounded central moment of order \(p\), with \(1 < p \le 2\).

They show that a schedule needing neither the horizon nor a confidence level attains \(\tilde O(t^{-\beta_p})\) at all times, also almost surely, where \(\beta_p = 2(p-1)/(3p-1)\), and that no rule stepping along the stochastic gradient at the current iterate can do better, even with adaptive steps and thresholds. With a known horizon \(T\) the optimal rate is \(O(T^{-\alpha_p})\) with \(\alpha_p = (p-1)/p\); under finite variance the three exponents are \(1/2\), \(2/5\) and \(1/3\), the last being the previous best time-uniform rate.

The result settles a conjecture from ICLR 2026 negatively for the unknown-horizon case. Querying gradients at the running average recovers \(\tilde O(t^{-\alpha_p})\) at all times, while heavy-ball momentum with geometric forgetting cannot beat \(\beta_p\).